A 18 g sample of metal is heated to 96°C and placed in a calorimeter containing 21 g of water at an initial temperature of 24°C. After the metal cools in the water bath, the final temperature inside the calorimeter is 26°C. What is the (positive) specific heat of the metal rounded to the HUNDREDTHS place? (hint: final temperatures of metal and water are the same). Do NOT include units. *

140

Explanation:

Given the following :

Mass of metal = 18g = 0.018kg

Mass of water (calorimeter) = 21g = 0.021kg

Initial temperature of metal = 273 + 96 = 369k

Initial temperature of water = 273 + 24 = 297k

Final temperature inside calorimeter = 273 + 26 = 299k

Temperature change of metal = 299 - 369= -70k

Temperature change of water = 299 - 297 = 2k

H = mc ΔT

m = mass

c = specific heat capacity

ΔT = change in temperature

Heat lost by metal = heat gained by water

mc ΔT = mc ΔT

Specific heat capacity of water = 4200

18 * C * ( 299 - 369 ) = 21 * 4.2 * ( 299 - 297)

0.018 × C × -70 = 0.021 × 4.2 × 2

- 1.26 × C = 0.1764

C = 176.4/1.26

C = 140

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.