After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 milliliters of a new solution. How would this be prepared? Add 25.0 milliliters of the stock solution to a volumetric flask, then add 100.0 milliliters of water. Add 25.0 milliliters of the stock solution to a volumetric flask, then add water to a total volume of 100.0 milliliters. Add the stock solution and water in equal amounts until 100.0 milliliters is reached. Add 25.0 milliliters of water to a volumetric flask, then add the stock solution to reach a total volume of 100.0 milliliters.

did anyone actually do this? like if anyone has submitted this i rly need .

it's 3.2 on edge, i just took the test.

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

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