he two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) + 5 I-(aq) + 6 H+(aq) --> 3 I2(aq) + 3 H2O(l) followed by reaction of the I2: I2(aq) + 2 S2O32- --> 2 I-(aq) + S4O62-(aq). What is the stoichiometric factor, that is the number of moles of Na2S

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

catya that's not even a b or c

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

answerleaving cheese out to get moldy;