Chemistry, 09.06.2020 02:57 ashleyaparicio7116
I’ve gotten the answer as x=.478 but when plugging back in, .46/.478 ≠ .22. Help please
Answers: 2
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Be sure to answer all parts. the following equilibrium constants were determined at 1123 k: c(s) + co2(g) ⇌ 2co(g) k'p = 1.30 × 1014 co(g) + cl2(g) ⇌ cocl2(g) k''p = 6.00 × 10−3 calculate the equilibrium constant at 1123 k for the reaction: c(s) + co2(g) + 2cl2(g) ⇌ 2cocl2(g) 4.68 × 10 9 (enter your answer in scientific notation.) write the equilibrium constant expression, kp:
Answers: 3
I’ve gotten the answer as x=.478 but when plugging back in, .46/.478 ≠ .22. Help please
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