Chemistry, 09.06.2020 07:57 savthespice
3 AsO4-3 + 5 PbCl2 ---> Pb5(AsO4)3Cl(s) + 9 Cl-
Your goal here is to determine what is left over when we mix a diluted solution that contains 0.518 g of arsenate with 2.21 g of lead(II) chloride.
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How much of each of the reactants will be left after the reaction is completed?
g of arsenate
g of lead(II) chloride
Answers: 1
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3 AsO4-3 + 5 PbCl2 ---> Pb5(AsO4)3Cl(s) + 9 Cl-
Your goal here is to determine what is left over...
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