If .654 g of oxygen dissolves in 1.5 L of water at 1.65 atm, at what pressure would you be able to dissolve 1.35 g in the same amount of water?

Explanation:

Hello,

In this case, we first compute the moles of oxygen in 0.654 g and 1.35 g by using its molar mass (32 g/mol):

Then, by using the ideal gas equation at the both states, given the same both temperature and volume:

We compute the volume at the second moles:

Best regards.

the answer for sodium is 0.186

the answer for rubidium is 0.251