Determine the temperature of 2.49mol of a gas contained in a 1.00L vessel at a pressure of 1.41atm. A. 345K

B. 159K

C. 18.7K

D. 6.90K

T=6.90 K

Explanation:

For this problem, you would use Ideal Gas Law.

P=pressure

V=volume

n=moles

R=ideal gas constant

T=temperature (in Kelvin)

We can fill in these values with what we are given.

P=1.41 atm

V=1.00 L

n=2.49 mol

R=0.08206 Latm/Kmol

T=?K

Since we are looking for T, we can get T alone.

With significant figures, we get .

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."