Assuming that the proximal histidine has a pKapKa of 6.00,6.00, you can use the Henderson–Hasselbalch equation to determine that the ratio of deprotonated to protonated histidines would be approximately 25:125:1 at a biological pHpH of 7.40.7.40. pH=pKa+log([A−][HA]) pH=pKa+log([A−][HA]) What would the ratio of deprotonated to protonated histidines be if the pHpH decreased to 6.40?

a is the answer

explanation:

which statement about trans-fatty acids is false?

a. the conversion of cis-fatty acids to trans-fatty acids is inhibited by the presence of antioxidants.

hope this

im pretty sure its b

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8