How many liters of 0.3m h3po4 are needed to neutralize 3.5l of 3m naoh

Explanation:

Hello,

In this case, given the reaction:

We notice a 3:1 molar ratio between sodium hydroxide and phosphoric acid, therefore, at the equivalence point we have:

That in terms of molarity is:

Se we solve for the volume of acid:

Best regards.

11.7 L

Explanation:

How many liters of 0.3M H₃PO₄ are needed to neutralize 3.5L of 3M NaOH?

Step 1: Write the balanced equation

H₃PO₄ + 3 NaOH = Na₃PO₄ + 3 H₂O

Step 2: Calculate the reacting moles of sodium hydroxide

3.5 L of 3 M NaOH were employed. The reacting moles of NaOH are:

Step 3: Calculate the reacting moles of phosphoric acid

The molar ratio of H₃PO₄ to NaOH is 1:3. The reacting moles of H₃PO₄ are (1/3) × 10.5 mol = 3.5 mol

Step 4: Calculate the required liters of phosphoric acid

3.5 moles of 0.3 M H₃PO₄ were employed. The required volume of H₃PO₄ is:

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l

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