What is the concentration of potassium ions in 153 mLof a 1.25 M K3PO4 solution

The concentration of potassium (K⁺) ions in the solution of 153 mL of 1.25 M K₃PO₄ is 3.75 moles

Explanation:

The parameters given are;

Volume of K₃PO₄ = 153 mL = 0.153 L

Concentration of K₃PO₄ = 1.25 M

The ionization of K₃PO₄ is as follows;

K₃PO₄ ⇄ 3·K⁺ (aq) + PO₄³⁻ (aq)

Therefore, 1 mole of K₃PO₄, produces 3 moles of potassium (K⁺) ions

Hence, the number of moles of K₃PO₄ in 153 mL of 1.25 M K₃PO₄ is found as follows;

153 mL of 1.25 M K₃PO₄ = 0.153 L of 1.25 M K₃PO₄

The number of moles present in 0.153 L of 1.25 M K₃PO₄ = 0.153 × 1.25 moles

The number of moles present in 0.153 L of 1.25 M K₃PO₄ = 0.19125 moles of K₃PO₄

Since 1 mole of K₃PO₄ produces 3 moles of potassium (K⁺) ions we have;

0.19125 moles of K₃PO₄ will produce, 3 × 0.19125 moles of potassium (K⁺) ions which gives;

0.19125 moles of K₃PO₄ will produce 0.57375 moles of potassium (K⁺) ions

Therefore, the amount of moles of potassium (K⁺) ions in 153 mL = 0.57375 moles

The the amount of moles of potassium (K⁺) ions in 1 L (1000 mL) = (1000/153) × 0.57375 moles

The the amount of moles of potassium (K⁺) ions in 1 L = 3.75 moles

Therefore, the concentration of potassium (K⁺) ions in the solution of 153 mL of 1.25 M K₃PO₄ = 3.75 moles.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

if you're asking what comes out, it's steam.