How many grams of carbon dioxide are in 88.5 L at STP?

173.8g

Explanation:

STP means standard temperature and pressure

The temperature there is 273k while the pressure is 1 atm

now we are to use the ideal gas equation to get the number of moles first

Mathematically;

PV = nRT

here P = 1 atm

V = 88.5 L

n = ?

R = molar gas constant = 0.082 L atm mol^-1 K^-1

Now rewriting the equation we can have

n = PV/RT

plugging the values we have

n = (1 * 88.5)/(0.082 * 273)

n = 88.5/22.386

n = 3.95 moles

Now we proceed to get the mass

Mathematically;

mass = no of moles * molar mass

molar mass of carbon iv oxide is 44g/mol

mass = 3.95 * 44 = 173.8 g

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