Find the volume of a right circular cone that has a height of 19.7 ft and a base with a diameter 9 ft. Round your answer to the nearest tenth of a cubic foot.

V = 417.8 ft³

Explanation:

The volume (V) of a right circular cone can be calculated as follows:

Where:

r: is the radius of the circular cone

h: is the height of the circular cone = 19.7 ft

The radius of the circular cone can be found using the diameter (d) of the cone's base:

Now, the volume is:

Therefore, the volume of a right circular cone is 417.8 ft³.

I hope it helps you!

whats the meaning of /

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j