Name the following alkanes

1. 2–methylbutane

2. 3,4,6–trimethyloctane

3. 3,3–diethylpentane.

Explanation:

To name the compound, we must do the following:

1. Locate the longest continuous carbon chain. This gives the parent name of the compound.

2. Identify the substituent attached.

3. Give the substituents the lowest possible count.

4. Combine the above to get the name of the compound.

Now, let us name the compound given in the question.

1a. The longest continuous carbon chain is carbon 4 i.e butane.

b. The substitute attached is CH3 i.e methyl.

c. The position of the methyl is at carbon 2.

d. The name of the compound is:

2–methylbutane.

2a. The longest continuous carbon chain is carbon 8 i.e octane

b. The substitute attached is CH3 i.e methyl.

c. The position of the methyl is at carbon 3, 4 and 6

d. The name of the compound is:

3,4,6–trimethyloctane.

3a. The longest continuous carbon chain is carbon 5 i.e pentane

b. The substitute attached CH2CH3 i.e ethyl.

c. The position of the ethyl is at carbon 3 and 3 i.e ethyl appears twice at carbon 3.

d. The name of the compound is:

3,3–diethylpentane.

a. they are both space stations

happy to

pls mark as brainliest.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.