A sample of 0.3220 g of an ionic compound containing the iodide ion (I-) is dissolved in water and treated with an excess of AgHCO3. If the mass of the AgI precipitate that forms is 0.235 g, what is the percent by mass of I in the original compound? The molar mass of AgI is 234.8 g.

39.44 %

Explanation:

Step 1: Write the balanced equation

I⁻(aq) + AgHCO₃(aq) = AgI(s) + HCO₃⁻(aq)

Step 2: Calculate the moles corresponding to 0.235 g of AgI

The molar mass of AgI is 234.8 g/mol.

Step 3: Calculate the moles of I⁻ that form 1.001 × 10⁻³ mol of AgI

The molar ratio of I⁻ to AgI is 1:1. The reacting moles of I⁻ are 1/1 × 1.001 × 10⁻³ mol = 1.001 × 10⁻³ mol

Step 4: Calculate the mass corresponding to 1.001 × 10⁻³ mol of I⁻

The molar mass of I⁻ is 126.90 g/mol.

Step 5: Calculate the percent by mass of I⁻ in the original compound

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

i believe it is c.) 1575 j.