2-methyl-2-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymercuration-reduction. Draw the structure of the alkene that was used to prepare the alcohol in highest yield. You do not have to consider stereochemistry.

See the explanation

Explanation:

In this question, we have to synthesize a molecule in which the "OH" group is placed in the most substituted carbon. Therefore we have to use a markovnikov reaction to the synthesis. The hydroboration is anti-markovnikov and the oxymercuration-reduction is markovnikov, therefore the oxymercuration-reduction is our best choice.

Now, the double bond can be placed in different places. Because the "OH" would be added in the tertiary carbon of the double bond. So, we can use 2-methylhex-1-ene or 2-methylhex-2-ene.

See figure 1.

I hope it helps

why is arctic sea ice important? arctic sea ice keeps the polar regions cool and moderate global climate. sea ice has a bright surface; 80 percent of the sunlight that strikes it is reflected back into space. as sea ice melts in the summer, it exposes the dark ocean surface.

ill try to . no promises tho.

explanation: