What formula would I use if I was given [OH-] and wanted to find POH?* 1 point
pH = -log[H+]
[H+]= 10^-pH
pOH = -log [OH-]
O [OH-] = 10^-POH

pOH = -log[OH-]

Explanation:

Hello,

To calculate the pH or pOH of a substance, we relate it the negative logarithm of either the H+ or OH- concentration.

pOH is used to find the alkalinity of a solution my measuring the concentration of the hydroxide ion [OH-]. Solutions having a pOH value that is greater than 7 are said to be acidic while solutions with value less than 7 are alkaline.

pH = -log[H+]

While

pOH = -log[OH-]

Note: the pOH value of a solution depends on the concentration of the hydroxide ion in the solution.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.