An object has a mass of 10 kg. when a net force of 40 n north acts on the object, what is it’s acceleration ?

4m/s² north.

Explanation:

Data obtained from the question include the following:

Mass (m) = 10Kg

Force (F) = 40N North.

Acceleration (a) =...?

Force is simply the product of mass and acceleration. It is represented mathematically as:

Force (F) = Mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain the acceleration of the object as follow:

40 = 10 x a

Divide both side by 10

a = 40/10

a = 4m/s²

Since the force was applied in the north direction, the object will also accelerate in the north direction. Therefore, the acceleration of the object is 4m/s² north.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :