How many liters of 4.0 M NaOH solution will react with 1.8 mol H2SO4? (Remember to balance the equation.) H2SO4 + NaOH → Na2SO4 + H2O

The correct answer is 0.9 Liters.

Explanation:

Based on the given reaction:  

2NaOH (aq) + H₂SO₄ (aq) ⇒ Na₂SO₄ (aq) + 2H₂O (l)

It is clearly evident from the reaction that one mole of sulfuric acid reacts with two moles of sodium hydroxide. So, 1.8 moles of H₂SO₄ will react with,  

2/1 × 1.8 mol = 3.6 moles of NaOH

The molarity or M of NaOH given is 4.0 M, the moles of NaOH given is 3.6. Now the volume of NaOH can be determined by using the formula,  

Molarity = no of moles/volume in Liters

4.0 = 3.6/V

V = 3.6/4.0 = 0.9 L

Hence, 0.9 Liters of 4.0 M NaOH will react with 1.8 moles of H₂SO₄.  

i would say b

explanation:

but i think i would need more information than that

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.