How would I find H3O in this problem using the PH

2.9x10^–8 M

Explanation:

Data obtained from the question include the following:

pH = 7.54

Concentration of hydronium ion, [H3O+] =.?

The Concentration of hydronium ion, [H3O+] can be obtain as follow:

pH = - log [H3O+]

7.54 = - log [H3O+]

- 7.54 = log [H3O+]

[H3O+] = Antilog (-7.54)

[H3O+] = 2.9x10^–8 M

Therefore, The concentration of hydronium ion, [H3O+] is 2.9x10^–8 M

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