An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder is Pf=1.24 atm. What is the enthalpy change for this process? ΔH =

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

Whereas the change in the internal energy is computed by:

So we compute the initial and final temperatures for one mole of the ideal gas:

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

Then, the volume-pressure product in Joules:

Finally, the change in the enthalpy for the process:

Best regards.

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

c, liquids evaporate, creating a gas