112,300 joules heat is transferred when 240 g of a metal sample is cooled from 880 °C to 13 °C. What
is the specific heat of this metal?

0.54 J/goC

Explanation:

Recall that we define the heat transferred as ;

H= mcθ

Where;

H= heat transferred = 112300J

m= mass of the metal= 240g or 0.24 Kg

c= specific heat capacity of the metal = the unknown

θ= change in temperature = (880°C-13°C) = 867°C

Substituting values and making the specific heat capacity the subject of the formula;

c= H/mθ

c= 112300/ 240×867

c= 0.54 J/goC

Hence, the specific heat capacity of the metal is 0.54 J/goC.

the volume increases