How many grams of chlorine gas are needed to react with 3.5 liters of a 1.7 molar potassium bromide solution?
Cl2 + 2 KBr - 2 KCl + Br2

211.2 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 1.7 M

Volume of solution = 3.5 L

Putting values in equation 1, we get:

The balanced chemical reaction is:

According to stoichiometry:

2 mole of KBr requires = 1 mole of

5.95 moles of KBr requires = moles of

Mass of

Thus 211.2 grams of chlorine gas are needed to react with 3.5 liters of a 1.7 molar potassium bromide solution

it is a good conductor

explanation: