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A. The pH is 4.66

B. The pH is 3.44

C. The pOH is 11.54

Explanation:

A. Data obtained from the question include:

Hydrogen ion concentration, [H+] = 2.17x10^-5 M

pH =.?

pH is simply defined as the negative logarithm of the hydrogen ion concentration. Mathematically, it is expressed as:

pH = - log [H+]

With the above formula, we can calculate the pH of the solution as follow:

pH = - log [H+]

[H+] = 2.17x10^-5 M

pH = - log 2.17x10^-5

pH = 4.66

Therefore, the pH of the solution is 4.66.

B. Data obtained from the question include:

pOH = 10.56

pH =.?

The pH and the pOH of a solution are related with the following equation:

pH + pOH = 14

Thus, with the above equation, we can obtain the pH of the solution as illustrated below:

pH + pOH = 14

pOH = 10.56

pH + 10.56 = 14

Collect like terms

pH = 14 - 10.56

pH = 3.44

Therefore, the pH of the solution is 3.44.

C. The following data were obtained from the question:

Hydrogen ion concentration, [H+] = 3.48x10^-3 M

pOH =.?

First, we shall determine the hydroxide ion concentration, [OH-] in the solution.

This is illustrated below:

[H+] x [OH-] = 1x10^-14 M²

[H+] = 3.48x10^-3 M

3.48x10^-3 M X [OH-] = 1x10^-14 M²

Divide both side by 3.48x10^-3 M

[OH-] = 1x10^-14 M²/3.48x10^-3 M

[OH-] = 2.87x10^-12 M

Now, we can determine the pOH of the solution as follow:

pOH = - log [OH-]

[OH-] = 2.87x10^-12 M

pOH = - log 2.87x10^-12

pOH = 11.54.

Therefore, the pOH of the solution is 11.54.

your answers are a,b,,e and f

i hope this

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they're all from the same group as sulfur (group 16).