I enjoy iced tea all year, but I especially enjoy it on a hot summer day. I make it by steeping the tea in hot water and then pouring the result over ice to cool and dilute it. If the tea cools to 95.0°C as it steeps, and I immediately pour 1.00L of hot tea over 1.00kg of ice, what will the final temperature be? Suppose I'm thirsty, because it's 26.1°C in my apartment. As soon as the tea is ready, I take my favorite glass (which weighs 435g-yes, I actually checked) and pour 500.0mL of the freshly-cooled tea into it. Assuming that I haven't pre-chilled the glass or added any ice, what will the final temperature of the tea be? Potentially-useful information and assumptions:
Assume that all the ice melts, that no heat is lost to the surroundings, that everything is stirred so that the temperature is uniform, and that the glass starts at the same temperature as my apartment but then equilibrates with the tea poured in. We can regard the tea as being dilute enough to have the same density (1.00g/mL) and specific heat (4.184 J/g. oC) as water. Assume that glass has a specific heat of 0.840 J/g. oC. The molar heat of fusion for water is 6.02 kJ/mol.