Potassium occurs naturally as two isotopes. The heavier atom has percentage abundance of 93.1 the lighter atom has mass number of 39 and the heaver one 41. The lighter atom has proton number 19. (i) Give the chemical symbol for potassium
(ii) Give the representation of the two isotopes of potassium.
(iii) What is the proton number of the heavier atom?
(iv) Calculate the relative atomic mass of potassium from the information given
to three significant figures.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

what does the table look like

its first and third is your answer i did the qustion the fourth isnt right