You wish to make a 0.289 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 100 mL of the dilute solution

Explanation:

Hello,

In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:

That in terms of molarities and volumes is:

Whereas is the initial molarity (3.00 M) of the stock solution, the molarity of the diluted solution (0.289 M), the aliquot of the stock (concentrated) solution and the volume of the diluted solution (100 mL), thus, we compute as required:

Best regards.

it takes on an electronical energy