A compound has 15.39 g of gold for every 2.77 g of chlorine. Simplified, there is __ g of gold for every 1 g of chlorine.

(Round to two decimal places)

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The question is to determine the simplest mass ratio of gold to Chlorine in the compound.

Since the mass of gold in the compound compared to chlorine is 15.39 g for every 2.77 g, the mass of gold per gram of chlorine is given as:

15.39 / 2.77 = 5.56 g of gold to two decimal places

Therefore, for every 5.56 g of gold, there is 1 g of chlorine.

Note : The ratio in which different elements combine by mass to form a compound is given by the law of constant composition which states that, "all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

you gotta add the following molecules so we can give u an answer

explanation: