Electrolysis is used to silver plate an iron spoon by placing it in a solution containing Ag+ ions and connecting the spoon and a silver electrode to a battery. Enter the half‑reaction that takes place when the spoon is plated with silver. Include phases.

The half-reaction for the electrolysis for the deposition of Ag on the spoon has been:

Electrolysis has been performed for the thin plating of metal under the influence of the electric field. The electrodes have been the source for the oxidation and reduction in the solution.

At the cathodic end, the reduction takes place. The reduction has been the gain of electrons.

The half-reaction for cathode has been:

The oxidation takes place at the anode. Oxidation can be described as the loss of electrons.

The spoon to be plated has been placed at the cathodic end, and there has been deposition of the solid Ag to the spoon.

For more information about electrolysis, refer to the link:

link

Ag(s) → Ag ⁺ (aq)  +  e⁻

Ag ⁺ (aq)  +  e⁻  →  Ag(s)

Explanation:

Electroplating is a way of electrolysis, where  a thin layer of metal is used to plate a determined object. It is a kinda process to purify a material you want.

The anode contains the metal you want to plate with, in this case, the Ag.

Anode contains the half reaction of oxidation so:

Ag(s) → Ag ⁺ (aq)  +  e⁻

In the cathode, you have the spoon, where it takes place the half reaction of reduction:

Ag ⁺ (aq)  +  e⁻  →  Ag(s)

The electrolytic cell, where the redox reaction takes place, must be filled with a AgNO₃ solution.

Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.