How many grams of H2O will be formed when 32.0 g H2 is mixed with 84.0 g of O2 and allowed to react to form water

94.58 g of

Explanation:

For this question we have to start with the reaction:

Now, we can balance the reaction:

We have the amount of  and the amount of . Therefore we have to find the limiting reactive, for this, we have to follow a few steps.

1) Find the moles of each reactive, using the molar mass of each compound ( ).

2) Divide by the coefficient of each compound in the balanced reaction ("2" for and "1" for ).

Find the moles of each reactive

Divide by the coefficient

The smallest values are for , so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:

We have to remember that the molar ratio between and is 2:2 and the molar mass of is 18 g/mol.

i'm wiling to try and you : )

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