Question 4
1 pts
How many moles of chromium are 1.5 x 10^24 atoms?

Using N = n × L

L = Avogadro's constant =6.02 ×10^23

n = number of moles

N = Number of entities

N = 1.5 × 10^24

n = N /L

n = 1.5×10^24/6.02×10^23

n = 2.49 moles

Hope this helps.

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