A mixture contains 21.7 g NaCl, 3.74 g KCI, and 9.76 g Lici.
How many moles of NaCl are in this
mixture?

(Molar Mass)
NaCl: 58.44 g/mol
KCI: 74.55 g/mol
LiCl: 42.3

0.371mol

Explanation:

The number of moles of a compound, denoted by n, can be calculated by dividing its mass in grams (g) by its molecular mass in grams per mol (g/mol).

Mathematically; n = mass of compound/ molar mass

According to the question, a mixture contains 21.7 g NaCl,

3.74 g KCI, and 9.76 g LiCl. In order to calculate the number of moles of NaCl in the mixture, we only need to use the mass NaCl compound occupies in the total mixture, which is 21.7g.

The molar mass of NaCl has been given as 58.44g/mol.

Hence, using the formula, we have;

Number of moles (n) = 21.7g / 58.54g/mol

n = 0.3713210

Approximately, n = 0.371mol

Therefore, 0.371mol of NaCl are present in the mixture.

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