The formula of the gas ozone is O 3. What is the volume of 48g of ozone at r. t.p?

1.8 x 10^ 24 atoms of oxygen

Explanation:

The molecular weight of ozone is known to be 48 grams / mol. Here we are given a sample of 48 grams of ozone as well, so in 48 grams of ozone the number of moles = 48 / 48 = 1,

1 mole of ozone is equal to 6.0221415 × 10^23 molecules of ozone. Respectively, 1 molecule of ozone has 3 atoms of oxygen. Thus, you can conclude the following -

3 * 6.0221415 × 10^23 =  ( About ) 1.8 x 10^ 24 atoms of oxygen

Hope that helps!