The structures of four organic compounds are shown below. Which statement is not correct? A. Only one of the compounds is an alcohol.
B. Only one of the compounds is an alkane .
C. Only one of the compounds is unsaturated
D. Only three of the compounds are hydrocarbons.

Option B. Only one of the compounds is an alkane

Explanation:

To know which option is wrong us, we simply determine the class to which each diagram belongs.

Diagram 1:

CH4 is called methane and it is a member of the alkane series which are saturated hydrocarbon.

Diagram 2:

CH3CH3 is called ethane and it is a member of the alkane series which are saturated hydrocarbon.

Diameter 3:

CH2=CH2 is called ethene and it is a member alkene series which are unsaturated hydrocarbon.

Diagram 4:

CH3CH2OH is called ethanol which is a member of the alcohol family. CH3CH2OH is also a saturated alcohol as it only contains single bonds.

From the above, we can see that:

1. Only one compound is alcohol i.e CH3CH2OH.

2. There are two members of the alkane series i.e CH4 and CH3CH3.

3. Only one compound is unsaturated i.e CH2=CH2. Unsaturated compound has one or more double bond.

4. Only three compounds are hydrocarbon i.e CH4, CH3CH3 and CH2=CH2. Hydrocarbons are compounds containg only carbon and hydrogen.

Therefore, option B is wrong as there are two members of the alkane present.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante