H2 + Br2 → 2HBr If 2.23 g of hydrogen (H2) reacts completely, how many grams of hydrogen bromide (HBr) is formed? (mw Br=79.9) Question 16 options: A) 2.21 g of HBr B) 179 g of HBr C) 82.13 g of HBr D) 80.92 g of HBr

The correct option is;

B) 179 g

Explanation:

The parameters given are;

Mass of H₂ that takes part in the reaction = 2.23 g

Molar mass of hydrogen gas, H₂ = 2.016 g

Number of moles, n, of hydrogen gas H₂ is given by the relation;

Chemical equation for the reaction;

H₂ + Br₂ → 2HBr

Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr

1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr

The molar mass, of HBr = 80.91 g/mol

The mass of HBr produced = Molar mass of HBr × Number of moles of HBr

The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams

Therefore, the correct option is B) 179 g.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles