How many moles of nitrogen, N, are in 61.0 g of nitrous oxide, N2O?

2.77 mol N

Explanation:

M(N2O) = 2*14 + 16 = 44 g/mol

61.0 g * 1 mol/44g = (61/44) mol N2O

                       N2O 2N

                    1 mol         2 mol

            (61/44) mol        x mol

x = (61/44)*2/1 = 2.77 mol N

idk i’m struggling too

a:

by the combination of an unlimited number of elements