g A 100.0 mL100.0 mL solution of 0.0200 M Fe3 0.0200 M Fe3 in 1 M HClO41 M HClO4 is titrated with 0.100 M Cu 0.100 M Cu , resulting in the formation of Fe2 Fe2 and Cu2 Cu2 . A PtPt indicator electrode and a saturated Ag||AgClAg|AgCl electrode are used to monitor the titration. Write the balanced titration reaction.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

No because it not possibly