A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is the partial pressure of gas Y? Use StartFraction P subscript A over P subscript T EndFraction equals StartFraction n subscript a over n subscript T EndFraction.. 0.50 atm 1.6 atm 2.1 atm 2.8 atm

1.6 atm

Explanation:

Data obtained from the question include:

Mole of Gas X = 2 moles

Mole of Gas Y = 6 moles

Total pressure = 2.1 atm

Partial pressure of Y =?

Next, we shall determine the mole fraction of of Gas Y.

This can be obtained as shown below:

Total mole = mole of Gas X + mole of Gas Y

Total mole = 2 + 6 = 8 moles.

Mole fraction of Gas Y = mole of Gas Y/ Total mole

Mole fraction of Gas Y = 6/8 = 0.75

Now, we can calculate the partial pressure of Gas Y as follow:

Mole fraction of Gas Y = 0.75

Total pressure = 2.1 atm

Partial pressure of Gas Y =?

Partial pressure of Gas Y = mole fraction of Gas Y x Total pressure

Partial pressure of Gas Y = 0.75 x 2.1

Partial pressure of Gas Y = 1.6 atm

Therefore, the Partial pressure of Gas Y is 1.6 atm.

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im not exactly sure but i think its b!