0.513 mol Al2O3 = g Al2O3

Molar mass (M) = mass(m) / number of moles (n)

To find the mass of Al2O3 first calculate it's molar mass

thus

M(Al2O3) = (27×2) + (16 × 3)

= 54 + 48

= 102g/mol

Mass of Al2O3 = molar mass × number of moles

= 102 × 0.513

= 52.326g of Al2O3

Hope this helps

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole