What is T2, if T1= 500 k, v1=10L, V2=8L, P1=600 torr, P2=200 torr?

T2 = 133.333°K

Explanation:

Using Combined Gas Laws:

(600 torr)(10L)/500°K = (200 torr)(8L)/x°K

Cross multiply:

x°K (600 torr)(10L) = 500°K(200 torr)(8L)

Divide:

x°K = (500°K(200 torr)(8L))/(600 torr)(10L)

x = 400/3°K or 133.333°K

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