A compound contains 28.6 magnesium 14.3 carbon 57.1 oxygen what is the empirical formula

Option 3

Explanation:

These are the steps for empirical forumla

1) If given percentage, assume everything in grams

2) Convert those grams to moles (using specific molar mass of each unique element)

3) Divide all the moles by the smallest mole you discovered.

4) Answer will be close to a whole number for each element and that's the answer.

First step, 28.6 g Mg, 14.3 g C, 57.1 g O

Second step:

28.6/24.305 = 1.1767 Mg

14.3/12.01= 1.1907 C

57.1/16.00 = 3.5688 O

Third step:

1.1767/1.1767 = 1 Mg

1.1907//1.1767 ~ 1 C

3.5688/1.1767 ~ 3 O

Put everything together you get!

mol/g

explanation:

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