Chemistry, 09.07.2020 02:01 germainenez3288

The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 3.626 g sample of ether was combusted in an oxygen rich environment to produce 8.612 g of CO2(g) and 4.406 g of H2O(g). Insert subscripts to complete the empirical formula of ether.

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Answer from: samarkanduzbek

$C_4H_{10}O$

Explanation:

Hello,

In this case, the first step is to compute the moles of carbon in the sample that are contained in CO2 only at the products as shown below:

$n_C=8.612gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2} =0.196molC$

Next the moles of hydrogen contained in the H2O only:

$n_H=4.406gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.490molH$

Now, we compute the mass of oxygen in the sample, by subtracting mass of both carbon and hydrogen from the 3.626 g of sample:

$m_O=3.626g-0.196molC*\frac{12gC}{1molC}-0.490molH*\frac{1gH}{1molH} =0.784gO$

And the moles:

$n_O=0.784gO*\frac{1molO}{16gO} =0.049molO$

Now, the mole ratios by considering the moles of oxygen as the smallest:

$C=\frac{0.196mol}{0.049mol}= 4\\\\H=\frac{0.49mol}{0.049mol}=10\\\\O=\frac{0.049mol}{0.049mol}=1$

Thus, empirical formula is:

$C_4H_{10}O$

Regards.

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

It has to be b i hope this

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