what is the maximum mass in grams of nh3 that can be produced by the reacion of 1g of n2 with 3g of h

4g of NH₃

Explanation:

Hello,

To solve this question, we'll require the equation of reaction.

Equation of reaction

N₂ + 3H₂ → 2NH₃

From the equation of reaction, 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

Number moles = mass / molar mass

Molar mass of H = 1.0g/mol

Mass of H₂ = 2 ×1 = 2g

Molar mass of N₂ = 14.0g/mol

Mass = 2 × 14 = 28g

Molar mass of NH₃ = 17g/mol

Mass = 17g

Therefore, 28g of N₂ reacts with 6g of H₂ to produce 34g of NH₃

I.e 28g + 6g(N₂ + H₂) = 34g of NH₃

34g of (N2 + H2) = 34g of NH₃

4g of (N2 + H2) = x g of NH₃

x = (4 × 34) / 34

x = 4g of NH₃

4g of NH₃ will be produced from 1g of N2 and 3g of H2

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