Question 3 (11 points) A gas has a volume of 690.0mL at -15.1°C and 392.0 mmHg. What would the volume of the gas be at
233.0°C and 0.700 atm of pressure? Answer with no decimal places.

V2 = 0.998L

v2 = 0.000998mL

Explanation:

P1 = 392mmHg

V1 = 690mL

T1 = -15.1°C = 257.9k

P2 = 0.700atm = 532mmHg

V2 = ?

T2 = 233°C = 506K

using general gas equation

P1V1/T1 = P2V2/T2

(392 x 690.0 x 10^-³)/257.9 =(532 x V2)/506

1.05=(532 x V2)/506

1.05 x 506 =(532 x V2)

531.3 =(532 x V2)

V2 = 531.3/532

V2 = 0.998L

v2 = 0.000998mL

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the temperature of the gas, in k, not celsius.