At what temperature is the following reaction feasible:
CaCO3 > CaO + CO2?
Enthalpy data:
CaCO3: -1207 kJ/mol
CaO: -635 kJ/mol
CO2: -394 kJ/mol
Entropy data:
CaCO3: +93 J/K mol
CaO: +40 J/K mol
CO2:+214 J/K mol
A. 1780 K
B.17 K
C. 1105.6 K
OD. 1.1K
Reset Selection

Option C. 1105.6 K

Explanation:

The following data were obtained from the question:

CaCO3 —> CaO + CO2

Enthalpy (H) data:

CaCO3 = -1207 kJ/mol

CaO = -635 kJ/mol

CO2 = -394 kJ/mol

Entropy (S) data:

CaCO3 = +93 J/K mol

CaO = +40 J/K mol

CO2 = +214 J/K mol

Temperature (T) =..?

Next, we shall determine the enthalphy change (ΔH).

This is illustrated:

CaCO3 —> CaO + CO2

CaCO3 = -1207 kJ/mol

CaO = -635 kJ/mol

CO2 = -394 kJ/mol

Heat of product (Hp) = -635 + -394 =

- 1029 KJ

Heat of reactant (Hr) = -1207 kJ/mol

Enthalphy change (ΔH) = Hp – Hr

Enthalphy change (ΔH) = - 1029 –(-1207)

Enthalphy change (ΔH) = 178 KJ/mol

Next, we shall determine the change in entropy (ΔS).

This is illustrated below:

CaCO3 —> CaO + CO2

Entropy (S) data:

CaCO3 = +93 J/K mol

CaO = +40 J/K mol

CO2 = +214 J/K mol

Entropy of product (Sp) = 40 + 214 =

+254 J/Kmol

Entropy of reactant (Sr) = +93 J/Kmol

Change in entropy (ΔS) = Sp – Sr

Change in entropy (ΔS) = 254 – 93

Change in entropy (ΔS) = 161 J/Kmol

Finally, we shall determine the temperature (T) at which the reaction was feasible.

This is illustrated below:

Enthalphy change (ΔH) = 178 KJ/mol = 178000 J/mol

Change in entropy (ΔS) = 161 J/Kmol

Temperature (T) =..?

ΔS = ΔH/T

161 = 178000/T

Cross multiply

161 x T = 178000

Divide both side by 161

T = 178000/161

T = 1105.6 K

Therefore, the temperature at which the reaction was feasible is 1105.6 K

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.

un recipient conține 6,4 moli de gaz. gazul hidrogen reprezintă 25% din totalul kilometrilor din container. în cazul în care presiunea totală este de 1.24 atm ceea ce este