Calculate the temperature at which the following reaction
becomes feasible:
4HCI + O2 -> 2Cl2 + 2H2O
Enthalpy: +280 kJ/mol
Entropy: +235 J/Kmol
A. 45.0 K
B. 65.80 K
C. 515.0 K
D. 1191.49 K
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Option D. 1191.49 K

Explanation:

The following data were obtained from the question:

Change in enthalphy (ΔH) = 280 kJ/mol

Change in entropy (ΔS) = +235 J/Kmol

Temperature (T) =...?

Next, we shall express the enthalphy in joule (J). This is illustrated below:

1 KJ/mol = 1000 J/mol

Therefore, 280 kJ/mol = 280 x 1000 = 280000 J/mol

Therefore, 280 KJ/mol is equivalent to 280000 J/mol

Now, we can obtain the temperature at which the reaction was feasible as follow:

ΔS = ΔH/T

235 = 280000/ T

Cross multiply

235 x T = 280000

Divide both side by 235

T = 280000/235

T = 1191.49 K

Therefore, the temperature at which the reaction was feasible is 1191.49 K

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