suppose 149 ml of a 0.181 m solution are added to a beaker containing 331 ml of water what is the finial concentration of the solution

0.0562 M

Explanation:

Number of moles before mixing = number of moles after mixing

M1V1 + M2V2 = M3V3

149*0.181 + 0*331 = M3(149 + 331)

149*0.181 = M3(149 + 331)

M3 = 149*0.181/(149 + 331) = 0.0562 M

am i too late?

explanation:

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