How many grams of solid Na2CO3 are required to neutralize exactly 2 liters of an HCI solution of pH 2.0?

The answer is 1.06g.

Explanation:

Analysis of question:

1. Identify the information in the question given.

2. What the question want?

Na2CO3 + 2HCl (arrow) 2NaCl + H20 + CO2

pH= -log[H+]

2.0= -log[H+]

log[H+]= -2.0

[H+]= 10 to the power of negative 2(10-2)

=0.01 mol dm-3

molarity of HCl is 0.01 mol dm-3

n=MV

=0.01 mol dm-3 × 2 dm3

=0.02 mol of HCl

Based on the chemical equation,

2.0 mol of HCl reacts with 1.0 mol of Na2CO3

0.02 mol of HCl reacts with 0.01 mol of Na2CO3

Na2CO3>a=1 mol

2HCl>b=2 mol

mass= number of mole × molar mass

g=0.01 × [2(23)+ 12+ 3(16)]

g=0.01 × 106

# =1.06 g.

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