If 56 J of heat is added to an aluminum can with a mass of 23.6 g , what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.

2.627775588 degrees Celsius (with 2 sig figs)

Explanation:

We need to use our equation q=m×s×(change in temp) and solve for our change in temperature. So divide both sides by m×s and you'll get:

Change in temp=q/(m×s) Where q= J of heat m=mass and s= specific heat

So now we just plug our numbers in:

56J/(23.6g×0.903J/g°C)= 2.627775588 and since 56 only has 2 sig figs, we round the final answer to 2.6°C

i dont know

explanation:

my dad did alot of meth and ace cheeks