Using the balanced equation below, how many grams of iron(iii) oxide would be required to make 187g iron Fe2O3+3CO = 2Fe+3CO2

267.14 iron oxide.

Explanation:

Given that

We know that molecular mass of iron-oxide = 160 g/mole.

We know that molecular mass of iron = 56 g/mole.

From the above reaction we can say that

1 mole of iron -oxide produce 2 mole of iron

160 gm of iron oxide produce 112 gm of iron

So

1 gm of iron required of iron oxide

Therefore

187 gm of iron required of iron oxide.

Therefore 187 gm of iron required 267.14 iron oxide.

it takes on an electronical energy

b) nuclear ive learned that in a pedtrodic table