If 1.00 mol of nitrogen monoxide gas and 1.00 mol of oxy-gen gas react, what is the limiting reactant and how many moles of NO2 are produced from the reaction

Limiting Reactant = NO

Number of moles of NO2 formed = 1

Explanation:

First thing's first, we have to write out the balanced chemical equatin. This is given as;

NO + O2   -->   NO2

Upon balancing we have;

2NO + O2 --> 2NO2

From the stoichiometry of the reaction, we can tell that 2 moles of NO reacts with 1 mole of O2 to form 2 moles of NO2.

If we have 1 mol of Nitrogen monoxide and 1 mol of oxygen, the limiting reactant is NO.

This is because 1 mol of No would require 0.5 mol of O2. So we have an excess of Oxygen while the NO has been used up.

Limiting reactant = NO

since the mole ratio between NO and NO2 is 2:2 it means that 1 mol of NO would also form 1 mol of NO2.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

the ratio of the conjugate base to the acid required to attain the desired ph.